ltr ilage maintenan f. anne vitaune f “gfd h a)o f’ f ‘* ” f f’It 0 a ill reven 2 2 r i f r to 2 0 1 I ite crho 7 0 7, 1 fe pub Â· : [ j ( to 02 itie â€ž i ” : r n t.Q: Why take the mean of this expression? My lecturer in introductory statistics has taken the mean of this equation: $$y=\frac{1+k-kx}{1+k-k^2}$$ This makes sense in the way that, when k is small, the equation takes on values close to zero, and the f(x) terms cancels with each other. However, why does he do it? Why doesn’t he just use the expression of the equation by itself? This would give a continuous function, whereas taking the mean gives a complicated function. Thank you. A: The mean is a “trick” to making the result of a function continuous. Let’s say you have $\int_a^b f(x)\,dx$. The mean of $f(x)$ might be $f(b)$ if $f$ is a continuous function. Or it might be $f(a)+f(b)$ if $f$ is step-like. In general, it is the Lebesgue integral of $f$. There is no such thing as the Lebesgue integral of a “step-like” function, as there is no way to choose the measure on the domain. Anti-hypoxia, anti-angiogenesis and anti-tumor activity of 7-O-alpha-D-glucopyranosyl-5-hydroxyfuro[2,3-g]-coumarin. A new furocoumarin, 7-O-alpha-D-glucopyranosyl-5-hydroxyfuro[2,3-g]-coumarin (I), was isolated from the roots of Fraxinus rhynchophylla Y. Hsiao. The structure of I was elucidated on the basis of spectral analysis (IR, UV, (1)H and (13)C NMR, DEPT, HMQC and HMBC). I exhibited potent