# Water Splash Photoshop Brushes

* If you don’t use Photoshop, now is a good time to learn to use it. It takes a little time to get into Photoshop’s layers and tools, but once you do, you will never look at digital images the same way.

Q: Returning an array from loop I have a rather simple problem, I am trying to build a paging library where the user can page through pictures, so I am trying to return a new array with each call to the API function. The problem arises from the fact that the results for each page are returned with their corresponding property. So var array1 = $array->page(0)->toArray(); will give me: Array ( [index] => 0 [car] => Porsche 911 [name] => Porsche 911 …etc… ) So I can just use array1[0] to get the first result and array1[1] to get the second result. Now when I get into the second loop of the API call I try to do the same thing: var array2 =$array->page(1)->toArray(); and because each subsequent page results are not inside an array like the first page I cannot use array2[1] to get the second result, I have to use array2. var array2 = $array->page(1)->toArray(); But then it only gives me the last result from the second page. I thought as it loops through the requests to collect the results it will use the first one to start the loop, so if the results are in that order (whereby I mean array(A,B,C,D)) it should start like this: A A A A A B B B B B C C C C C etc… But I do not know why it seems to stop at the last item I tried, because it got the result of the last page. I thought that by using: var array2 =$array->page(1)->toArray(); it would get the second page, then go to the next request (as it is now iterating array1) and return the results for the second page, but it seems to take the first array and starts with it as if it were the first page. Now I have also tried: var array2 = $array->page(1); and var array2 =$array->page(2); which did

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\DOC TRENC \BLOCK{TRENC} \iexhibit[typeoftheclause]{ (ENV (AX : OK) P Q R : OK) \ ->\ (ENV (AX : OK) P Q : OK) }\keyword{fol} If f, g are monotonic functions, then $f \in g$ $\forall x : A \; fx \in gx$ $\forall x : A \; fx \in \mathord{\swarrow}fx$ \end{block} \begin{block}{\TAG{TRENC\_S}}} \begingroup \renewcommand{ ormalsize}{\tiny} \iexhibit[commutative law]{ (ENV (AX : OK) P Q R : OK) \ ->\ (ENV (AX : OK) P R Q : OK) }\keyword{fol} If f, g are monotonic functions, then $\mathord{\swarrow}fx \in gx$ $\forall x : A \; \mathord{\swarrow}fx \in gx$ $\forall x : A \; gx \in \mathord{\swarrow}fx$ \end{block} \end{exercise} \end{document} A: The values of truth values are stored in datatype ℂ; it has an addition operation and a negation operation which denote \in and ot\in. What you are missing is the function λf.ℂ⊤~f; it takes a function and returns the pair ℂ and T. \documentclass[12pt]{exercises} \usepackage{amsmath,amssymb} \usepackage{amsthm,amsfonts} \usepackage{